Series Program in C 7

[(1^1)/1!] + [(2^2)/2!] + [(3^3)/3!] + [(4^4)/4!] + [(5^5)/5!] + ... + [(n^n)/n!]

Code:

double power(int a, int b)

{

    long i, p=1;

    for(i=1;i<=b;i++)

    {

        p=p*a;

    }

    return p;

}

double fact(int n)

{

    long i, f=1;

    for(i=1;i<=n;i++)

    {

        f=f*i;

    }

    return f;

}

int main()

{

    long i,n;

    double sum=0;

    n=5;

    for(i=1;i<=n;i++)

    {

        sum=sum+power(i,i)/fact(i);

    }

    printf("Sum: %lf",sum);

    return 0;

}

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