Code:
#include iostream
#include conio.h
using namespace std;
int main(void)
{
float a[10][10], b[10], x[10], y[10];
int n = 0, m = 0, i = 0, j = 0;
cout << "Enter size of 2d array(Square matrix) : ";
cin >> n;
for (i = 0; i < n; i++)
{
for (j = 0; j < n; j++)
{
cout << "Enter values no :(" << i << ", " << j << ") ";
cin >> a[i][j];
}
}
cout << "\nEnter Values to the right side of equation\n";
for (i = 0; i < n; i++)
{
cout << "Enter values no :(" << i << ", " << j << ") ";
cin >> b[i];
}
cout << "Enter initial values of x\n";
for (i = 0; i < n; i++)
{
cout << "Enter values no. :(" << i<<"):";
cin >> x[i];
}
cout << "\nEnter the no. of iteration : ";
cin >> m;
while (m > 0)
{
for (i = 0; i < n; i++)
{
y[i] = (b[i] / a[i][i]);
for (j = 0; j < n; j++)
{
if (j == i)
continue;
y[i] = y[i] - ((a[i][j] / a[i][i]) * x[j]);
x[i] = y[i];
}
printf("x%d = %f ", i + 1, y[i]);
}
cout << "\n";
m--;
}
return 0;
}
Output:
Enter size of 2d array(Square matrix) : 3
Enter values no :(0, 0) 2
Enter values no :(0, 1) 3
Enter values no :(0, 2) 1
Enter values no :(1, 0) 5
Enter values no :(1, 1) 4
Enter values no :(1, 2) 6
Enter values no :(2, 0) 8
Enter values no :(2, 1) 7
Enter values no :(2, 2) 9
Enter Values to the right side of equation
Enter values no :(0, 3) 2
Enter values no :(1, 3) 3
Enter values no :(2, 3) 4
Enter initial values of x
Enter values no. :(0): 0
Enter values no. :(1): 0
Enter values no. :(2): 0
Enter the no. of iteration : 4
x1 = 1.000000 x2 = -0.500000 x3 = -0.055556
x1 = 1.777778 x2 = -1.388889 x3 = -0.055556
x1 = 3.111111 x2 = -3.055555 x3 = 0.055555
x1 = 5.555555 x2 = -6.277777 x3 = 0.388889
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