Series Program in C 9

[(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n]

Code:

long power(int a, int b)

{

    long i, p=1;

    for(i=1;i<=b;i++)

    {

        p=p*a;

    }

    return p;

}

int main()

{

    long i,n;

    double sum=0;

    n=5;

    for(i=1;i<=n;i++)

    {

        sum=sum+(power(i,i)/i);

    }

    printf("Sum: %lf",sum);

    return 0;

}

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