1/2 - 2/3 + 3/4 - 4/5 + 5/6 - ...... n
Code:
Code:
int main()
{
double i,
n,sum=0;
n=10;
for(i=1;i<=n;i++)
{
if
((int)i%2==1)
sum+=i/(i+1);
else
sum-=i/(i+1);
}
printf("Sum: %lf",sum);
return 0;
}
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