Data Types Questions In C3

11. 

What is the output of this C code (on a 32-bit machine) ?

int main() 
{
 int x = 10000; 
double y = 56; 
int *p = &x; 
double *q = &y; 
printf("p and q are %d and %d", sizeof(p), sizeof(q));
 return 0; 
}

A. p and q are 4 and 4
B. p and q are 4 and 8
C. Compiler error
D. p and q are 2 and 8


Answer: A

Explanation:

Size of any type of pointer is 4 on a 32-bit machine. 

Output:
$ cc pgm6.c 
$ a.out 
p and q are 4 and 4

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12.

Which is correct with respect to size of the datatypes?

A. char > int > float
B. int > char > float
C. char < int < double
D. double > char > int

Answer: C

Explanation:

char has lesser bytes than int and int has lesser bytes than double in any system.

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13.

Which of the datatypes have size that is variable?

A. int
B. struct
C. float
D. double

Answer: B

Explanation:

Since the size of the structure depends on its fields, it has a variable size.

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14.

Predict the output

#include
int main()
{
float c = 5.0;
printf ("Temperature in Fahrenheit is %.2f", (9/5)*c + 32); 
return 0; 
}

A. Temperature in Fahrenheit is 41.00
B. Temperature in Fahrenheit is 37.00
C. Temperature in Fahrenheit is 0.00
D. Compiler Error

Answer: B

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Data Types Questions In C2

6. 

What will be output when you will execute following c code?

#include

enum A{

    x,y=5,

    enum B{

         p=10,q

    }varp;

}varx;

int main(){

    printf("%d %d",x,varp.q);
    return 0;

}

Choose all that apply:

A.	0 11
B.	5 10
C.	4 11
D.	0 10
E.	Compilation error

Answer. E

Explanation:

Turbo C++ 3.0: Compilation error

Turbo C ++4.5: Compilation error

Linux GCC: Compilation error

Visual C++: Compilation error

Nesting of enum constant is not possible in c.

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7.

What will be output when you will execute following c code?

#include

int main(){

    char a=250;

    int expr;

    expr= a+ !a + ~a + ++a;

    printf("%d",expr);
    return 0;

}

Choose all that apply:

A.	249
B.	250
C.	0
D.	-6
E.	Compilation error

Answer: D

Explanation:

Turbo C++ 3.0: -6

Turbo C ++4.5: -6

Linux GCC: -6

Visual C++: -6

char a = 250;

250 is beyond the range of signed char. Its corresponding cyclic value is: -6

So, a = -6

Consider on the expression:

expr= a+ !a + ~a + ++a;

Operator! , ~ and ++ have equal precedence. And it associative is right to left.

So, First ++ operator will perform the operation. So value a will -5

Now,

Expr = -5 + !-5 + ~-5 + -5

= -5 + !-5 + 4 - 5

= -5 + 0 + 4 -5

= -6

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8.

What is the range of signed int data type in that compiler in which size of int is two byte?

 A. -255 to 255

 B. -32767 to 32767

 C. -32768 to 32768

 D. -32767 to 32768

 E. -32768 to 32767

Answer: E

Explanation:

Size of int is always equal to word length of micro preprocessor in which your compiler has based.

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9.

Which of the following is integral data type?

A.	void
B.	char
C.	float
D.	double
E.	None of these

Answer: B

Explanation:

In c char is integral data type. It stores the ASCII value of any character constant.

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10.

What will be output when you will execute following c code?

#include

int main(){

    signed x,a;

    unsigned y,b;

    a=(signed)10u;

    b=(unsigned)-10;

    y = (signed)10u + (unsigned)-10;

    x = y;

    printf("%d  %u\t",a,b);

    if(x==y)

         printf("%d %d",x,y);

    else if(x!=y)

         printf("%u  %u",x,y);
    return 0;

}

Choose all that apply:

A.	10 -10   0 0
B.	10 -10   65516 -10
C.	10 -10   10 -10
D.	10 65526      0 0
E.	Compilation error

Answer: D

Explanation:

Turbo C++ 3.0: 10 65526 0 0

Turbo C ++4.5: 10 65526 0 0

Linux GCC: 10 4294967286 0 0

Visual C++: 10 4294967286 0 0

a=(signed)10u;

signed value of 10u is +10

so, a=10

 b=(unsigned)-10;

unsigned value of -10 is :

MAX_VALUE_OF_UNSIGNED_INT – 10 + 1

In turbo c 3.0 complier max value of unsigned int is 65535

So, b = 65526

y = (signed)10u + (unsigned)-10;

  = 10 + 65526 = 65536 = 0 (Since 65536 is beyond the range of unsigned int. zero is its corresponding cyclic vlaue)

X = y = 0

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Data Type Questions In C1

Defination: Data types in c refer to an extensive system used for declaring variables or functions of different types. 
The type of a variable determines how much space it occupies in storage and how the bit pattern stored is interpreted.

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Technical and Interview asked questions for placement in c programming language

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1.

Consider on following declaration in c:

(i) short const register i=10;

(ii) static volatile const int i=10;

(iii) signed extern float i=10.0;

(iv) unsigned auto long register i=10;

Choose correct one:

A.	Only (iv)is correct
B.	Only (ii) and (iv) is correct
C.	Only (i) and (ii) is correct
D.	Only (iii) correct
E.	All are correct declaration

Answer: C

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2.

Which of the following is a User-defined data type?

A. typedef int Boolean;

B. typedef enum {Mon, Tue, Wed, Thu, Fri} Workdays;

C. struct {char name[10], int age};

D. All of the mentioned

Answer: D

Explanation:

typedef and struct are used to define user-defined data types.

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3.

Comment on the output of this C code?

 int main()

 { int a[5] = {1, 2, 3, 4, 5}; 

int i; 

for (i = 0; i < 5; i++) 

if ((char)a[i] == '5')

 printf("%d\n", a[i]);

 else 

printf("FAIL\n"); 

}

A. The compiler will flag an error

B. Program will compile and print the output 5

C. Program will compile and print the ASCII value of 5

D. Program will compile and print FAIL for 5 times

Answer: D

Explanation:

The ASCII value of 5 is 53,

 the char type-casted integral value 5 is 5 only. 

Output: $ cc pgm1.c 

$ a.out 

FAILED 

FAILED 

FAILED

FAILED

FAILED

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4. 

Which of the following is a User-defined data type?

A. typedef int Boolean;

B. typedef enum {Mon, Tue, Wed, Thu, Fri} Workdays;

C. struct {char name[10], int age};

D. All of the mentioned

Answer: D

Explanation:

typedef and struct are used to define user-defined data types.

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5.

What is the size of an int data type?

A. 4 Bytes

B. 8 Bytes

C. Depends on the system/compiler

D. Cannot be determined.

Answer: C

Explanation:

The size of the data types depend on the system.

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