C Program to Support Infinite Precision Arithmetic & Store a Number as a List of Digits

Code:

#include   stdio.h
#include   stdlib.h
#include   ctype.h

struct node
{
    int num;
    struct node *next;
};

int feednumber(struct node **);
void release(struct node **);
void display(struct node *);

int main()
{
    struct node *p = NULL;
    int pcount = 0, qcount = 0;

    printf("Enter number of any length\n");
    pcount = feednumber(&p);
    printf("Number of integers entered are: %d\n", pcount);
    printf("Displaying the number entered:\n");
    display(p);
    release(&p);

    return 0;
}

/*Function to create nodes of numbers*/
int feednumber(struct node **head)
{
    char ch, dig;
    int count = 0;
    struct node *temp, *rear = NULL;

    ch = getchar();
    while (ch != '\n')
    {
        dig = atoi(&ch);
        temp = (struct node *)malloc(sizeof(struct node));
        temp->num = dig;
        temp->next = NULL;
        count++;
        if ((*head) == NULL)
        {
            *head = temp;
            rear = temp;
        }
        else
        {
            rear->next = temp;
            rear = rear->next;
        }
        ch = getchar();
    }

    return count;
}

/*Function to display the list of numbers*/
void display (struct node *head)
{
    while (head != NULL)
    {
        printf("%d", head->num);
        head = head->next;
    }
    printf("\n");
}

/*Function to free the allocated list of numbers*/
void release (struct node **head)
{
    struct node *temp = *head;

    while ((*head) != NULL)
    {
        (*head) = (*head)->next;
        free(temp);
        temp = *head;
    }
}


Output:

Enter number of any length
932429842394820948234948098391830283192193818310398291830131209
Number of integers entered are: 63
Displaying the number entered:
932429842394820948234948098391830283192193818310398291830131209


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