Sunday 12 November 2017

C Program to Print Nth Node from the last of a Linked List


Code:

#include   stdio.h
#include   stdlib.h

struct node
{
    int num;
    struct node *next;
};

void create(struct node **);
void nthnode(struct node *, int);
void release(struct node **);

int main()
{
    struct node *p = NULL;
    int n;

    printf("Enter data into the list\n");
    create(&p);
    printf("Enter the value n to find nth position from the last node: ");
    scanf("%d", &n);
    nthnode(p, n);
    release (&p);

    return 0;
}

void nthnode(struct node *head, int n)
{
    struct node *p, *q;
    int i;

    q = p = head;

    for (i = 0; i < n && q != NULL; i++)
    {
        q = q->next;
    }
    if (i < n)
    {
        printf("Entered n = %d is larger than the number of elements = %d in list. Please try again.\n", n, i);
    }
    else
    {
        while (q->next != NULL)
        {
            q = q->next;
            p = p->next;
        }
        printf("%d is %d nodes from the last node.\n", p->num, n);
    }
}

void create(struct node **head)
{
    int c, ch;
    struct node *temp, *rear;

    do
    {
        printf("Enter number: ");
        scanf("%d", &c);
        temp = (struct node *)malloc(sizeof(struct node));
        temp->num = c;
        temp->next = NULL;
        if (*head == NULL)
        {
            *head = temp;
        }
        else
        {
            rear->next = temp;
        }
        rear = temp;
        printf("Do you wish to continue [1/0]: ");
        scanf("%d", &ch);
    } while (ch != 0);
    printf("\n");
}

void release(struct node **head)
{
    struct node *temp = *head;
    *head = (*head)->next;
    while ((*head) != NULL)
    {
        free(temp);
        temp = *head;
        (*head) = (*head)->next;
    }
}

Output:

Enter data into the list
Enter number: 1
Do you wish to continue [1/0]: 1
Enter number: 2
Do you wish to continue [1/0]: 1
Enter number: 3
Do you wish to continue [1/0]: 1
Enter number: 4
Do you wish to continue [1/0]: 1
Enter number: 5
Do you wish to continue [1/0]: 0

Enter the value n to find nth position from the last node: 2
3 is 2 nodes from the last node.

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