C Program to Find the Second Largest & Smallest Elements in an Array

Code:
#include

void main ()
{
    int number[30];
    int i, j, a, n, counter, average;

    printf("Enter the value of N\n");
    scanf("%d", &n);
    printf("Enter the numbers \n");
    for (i = 0; i < n; ++i)
    scanf("%d", &number[i]);
    for (i = 0; i < n; ++i)
    {
        for (j = i + 1; j < n; ++j)
        {
            if (number[i] < number[j])
            {
                a = number[i];
                number[i] = number[j];
                number[j] = a;
            }
        }
    }
    printf("The numbers arranged in descending order are given below \n");
    for (i = 0; i < n; ++i)
    {
        printf("%d\n", number[i]);
    }
    printf("The 2nd largest number is  = %d\n", number[1]);
    printf("The 2nd smallest number is = %d\n", number[n - 2]);
    average = (number[1] + number[n - 2]) / 2;
    counter = 0;
    for (i = 0; i < n; ++i)
    {
        if (average == number[i])
        {
            ++counter;
        }
    }
    if (counter == 0 )
        printf("The average of %d  and %d is = %d is not in the array \n",
        number[1], number[n - 2], average);
    else
        printf("The average of %d  and %d in array is %d in numbers \n",
        number[1], number[n - 2], counter);
}


Output:

Enter the value of N
4
Enter the numbers
450
340
120
670
The numbers arranged in descending order are given below
670
450
340
120
The 2nd largest number is  = 450
The 2nd smallest number is = 340
The average of 450  and 340 is = 395 is not in the array

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