Saturday, 18 November 2017

C++ Program to Find Basis and Dimension of a Matrix


Code:

#include    conio.h
#include    iostream
#include    math.h

using namespace std;
double d = 0;
double det(int n, double mat[10][10]);
double det(int n, double mat[10][10])
{
    double submat[10][10];
    if (n == 2)
        return ((mat[0][0] * mat[1][1]) - (mat[1][0] * mat[0][1]));
    else
    {
        for (int c = 0; c < n; c++)
        {
            int subi = 0; //submatrix's i value
            for (int i = 1; i < n; i++)
            {
                int subj = 0;
                for (int j = 0; j < n; j++)
                {
                    if (j == c)
                        continue;
                    submat[subi][subj] = mat[i][j];
                    subj++;
                }
                subi++;

            }
            d = d + (pow(-1, c) * mat[0][c] * det(n - 1, submat));
        }
    }
    return d;
}
int main(int argc, char **argv)
{

    cout << "Enter the number of vectors:\n";
    int n;
    cin >> n;
    double mat[10][10];
    cout << "Enter the vectors one by one:\n";
    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < n; j++)
        {
            cin >> mat[j][i];
        }
    }
    d = det(n, mat);
    if (d != 0)
        cout << "The vectors forms the basis of R" << n
                << " as the determinant is non-zero";
    else
        cout << "The vectors doesn't form the basis of R" << n
                << " as the determinant is zero";

}


Output:

Enter the number of vectors:
3
Enter the vectors one by one:
1 2 3
2 3 4
3 4 5
The vectors doesn't form the basis of R3 as the determinant is zero

Enter the number of vectors:
4
Enter the vectors one by one:
2 3 5 8
1 6 2 9
3 4 2 7 
2 5 3 9
The vectors forms the basis of R4 as the determinant is non-zero




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