C Program to Count the Number of Trailing Zeroes in Integer

Code:

#include stdio.h>

void main()
{
    int j = 31, i, count = 0;
    unsigned int num;
    int b[32] = {0};

    printf("enter the number:");
    scanf("%d", &num);
    while (num != 0)
    {
        if (num & 1 == 1)
        {
            break;
        }
        else
        {
            count++;
            num = num >> 1;

        }
    }
    printf("\n%d", count);
}

Output:

enter the number:128
7

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