Monday 27 November 2017

Java Program to Implement Sorting of Less than 100 Numbers in O(n) Complexity


Code:

import java.util.Random;

public class Order_n_Sorting_Algorithm 
{
    static int[] sort(int[] sequence, int maxValue) 
    {
        // Bucket Sort
        int[] Bucket = new int[maxValue + 1];
        int[] sorted_sequence = new int[sequence.length];

        for (int i = 0; i < sequence.length; i++)
            Bucket[sequence[i]]++;

        int outPos = 0;
        for (int i = 0; i < Bucket.length; i++)
            for (int j = 0; j < Bucket[i]; j++)
                sorted_sequence[outPos++] = i;

        return sorted_sequence;
    }

    static void printSequence(int[] sorted_sequence) 
    {
        for (int i = 0; i < sorted_sequence.length; i++)
            System.out.print(sorted_sequence[i] + " ");
    }

    static int maxValue(int[] sequence) 
    {
        int maxValue = 0;
        for (int i = 0; i < sequence.length; i++)
            if (sequence[i] > maxValue)
                maxValue = sequence[i];
        return maxValue;
    }

    public static void main(String args[]) 
    {
        System.out
                .println("Sorting of randomly generated numbers using O(n) BUCKET SORT algorithm");
        Random random = new Random();
        int N = 25;
        int[] sequence = new int[N];

        for (int i = 0; i < N; i++)
            sequence[i] = Math.abs(random.nextInt(100));

        int maxValue = maxValue(sequence);

        System.out.println("\nOriginal Sequence: ");
        printSequence(sequence);

        System.out.println("\nSorted Sequence: ");
        printSequence(sort(sequence, maxValue));
    }

}



Output:

Sorting of randomly generated numbers using O(n) BUCKET SORT algorithm

Original Sequence: 
43 50 28 1 80 8 77 92 55 44 15 42 47 98 44 12 78 36 73 57 86 36 11 35 51 
Sorted Sequence: 
1 8 11 12 15 28 35 36 36 42 43 44 44 47 50 51 55 57 73 77 78 80 86 92 98



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