Tuesday, 28 November 2017

Java Program to Find Whether a Path Exists Between 2 Given Nodes


Code:

import java.util.HashMap;
import java.util.LinkedHashSet;
import java.util.LinkedList;
import java.util.Map;
import java.util.Scanner;
import java.util.Set;

public class Path_Between_Nodes
{
    private Map> map = new HashMap();

    public void addEdge(String node1, String node2)
    {
        LinkedHashSet adjacent = map.get(node1);
        if (adjacent == null)
        {
            adjacent = new LinkedHashSet();
            map.put(node1, adjacent);
        }
        adjacent.add(node2);
    }

    public void addTwoWayVertex(String node1, String node2)
    {
        addEdge(node1, node2);
        addEdge(node2, node1);
    }

    public boolean isConnected(String node1, String node2)
    {
        Set adjacent = map.get(node1);
        if (adjacent == null)
        {
            return false;
        }
        return adjacent.contains(node2);
    }

    public LinkedList adjacentNodes(String last)
    {
        LinkedHashSet adjacent = map.get(last);
        if (adjacent == null)
        {
            return new LinkedList();
        }
        return new LinkedList(adjacent);
    }

    private static String  START;
    private static String  END;
    private static boolean flag;

    public static void main(String[] args)
    {
        // this graph is directional
        Path_Between_Nodes graph = new Path_Between_Nodes();
        // graph.addEdge("A", "B");
        graph.addEdge("A", "C");
        graph.addEdge("B", "A");
        graph.addEdge("B", "D");
        graph.addEdge("B", "E"); 
        graph.addEdge("B", "F");
        graph.addEdge("C", "A");
        graph.addEdge("C", "E");
        graph.addEdge("C", "F");
        graph.addEdge("D", "B");
        graph.addEdge("E", "C");
        graph.addEdge("E", "F");
        // graph.addEdge("F", "B");
        graph.addEdge("F", "C");
        graph.addEdge("F", "E");
        LinkedList visited = new LinkedList();
        System.out.println("Enter the source node:");
        Scanner sc = new Scanner(System.in);
        START = sc.next();
        System.out.println("Enter the destination node:");
        END = sc.next();

        visited.add(START);
        new Path_Between_Nodes().breadthFirst(graph, visited);
        sc.close();
    }

    private void breadthFirst(Path_Between_Nodes graph,
            LinkedList visited)
    {
        LinkedList nodes = graph.adjacentNodes(visited.getLast());

        for (String node : nodes)
        {
            if (visited.contains(node))
            {
                continue;
            }
            if (node.equals(END))
            {
                visited.add(node);
                printPath(visited);
                flag = true;
                visited.removeLast();
                break;
            }
        }

        for (String node : nodes)
        {
            if (visited.contains(node) || node.equals(END))
            {
                continue;
            }
            visited.addLast(node);
            breadthFirst(graph, visited);
            visited.removeLast();
        }
        if (flag == false)
        {
            System.out.println("No path Exists between " + START + " and "
                    + END);
            flag = true;
        }

    }

    private void printPath(LinkedList visited)
    {
        if (flag == false)
            System.out.println("Yes there exists a path between " + START
                    + " and " + END);

        for (String node : visited)
        {
            System.out.print(node);
            System.out.print(" ");
        }
        System.out.println();
    }
}


Output:

Enter the source node:
E
Enter the destination node:
B
No path Exists between E and B

Enter the source node:
A
Enter the destination node:
E
Yes there exists a path between A and E
A C E 
A C F E


More Java Programs:















100+ Best Home Decoration Ideas For Christmas Day 2019 To Make Home Beautiful

Best gifts for Christmas Day | Greeting cards for Christmas Day | Gift your children a new gift on Christmas day This Christmas d...