Friday, 17 November 2017

Java Program to Find Inverse of a Matrix


Code:

import java.util.Scanner;

public class Inverse 
{
    public static void main(String argv[]) 
    {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter the dimension of square matrix: ");
        int n = input.nextInt();
        double a[][]= new double[n][n];
        System.out.println("Enter the elements of matrix: ");
        for(int i=0; i
            for(int j=0; j
                a[i][j] = input.nextDouble();

        double d[][] = invert(a);

        System.out.println("The inverse is: ");
        for (int i=0; i
        {
            for (int j=0; j
            {
                System.out.print(d[i][j]+"  ");
            }
            System.out.println();
        }
        input.close();
    }

    public static double[][] invert(double a[][]) 
    {
        int n = a.length;
        double x[][] = new double[n][n];
        double b[][] = new double[n][n];
        int index[] = new int[n];
        for (int i=0; i
            b[i][i] = 1;

 // Transform the matrix into an upper triangle
        gaussian(a, index);

 // Update the matrix b[i][j] with the ratios stored
        for (int i=0; i
            for (int j=i+1; j
                for (int k=0; k
                    b[index[j]][k]
                        -= a[index[j]][i]*b[index[i]][k];

 // Perform backward substitutions
        for (int i=0; i
        {
            x[n-1][i] = b[index[n-1]][i]/a[index[n-1]][n-1];
            for (int j=n-2; j>=0; --j) 
            {
                x[j][i] = b[index[j]][i];
                for (int k=j+1; k
                {
                    x[j][i] -= a[index[j]][k]*x[k][i];
                }
                x[j][i] /= a[index[j]][j];
            }
        }
        return x;
    }

// Method to carry out the partial-pivoting Gaussian
// elimination.  Here index[] stores pivoting order.

    public static void gaussian(double a[][], int index[]) 
    {
        int n = index.length;
        double c[] = new double[n];

 // Initialize the index
        for (int i=0; i
            index[i] = i;

 // Find the rescaling factors, one from each row
        for (int i=0; i
        {
            double c1 = 0;
            for (int j=0; j
            {
                double c0 = Math.abs(a[i][j]);
                if (c0 > c1) c1 = c0;
            }
            c[i] = c1;
        }

 // Search the pivoting element from each column
        int k = 0;
        for (int j=0; j
        {
            double pi1 = 0;
            for (int i=j; i
            {
                double pi0 = Math.abs(a[index[i]][j]);
                pi0 /= c[index[i]];
                if (pi0 > pi1) 
                {
                    pi1 = pi0;
                    k = i;
                }
            }

   // Interchange rows according to the pivoting order
            int itmp = index[j];
            index[j] = index[k];
            index[k] = itmp;
            for (int i=j+1; i
            {
                double pj = a[index[i]][j]/a[index[j]][j];

 // Record pivoting ratios below the diagonal
                a[index[i]][j] = pj;

 // Modify other elements accordingly
                for (int l=j+1; l
                    a[index[i]][l] -= pj*a[index[j]][l];
            }
        }
    }
}


Output:

Enter the dimension of square matrix: 
2
Enter the elements of matrix: 
1 2 
3 4 
The Inverse is: 
-1.9999999999999998  1.0  
1.4999999999999998  -0.49999999999999994



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