Code:
// Java program to find Index of 0 to be replaced with 1 to get
// longest continuous sequence of 1s in a binary array
import java.io.*;
class Binary
{
// Returns index of 0 to be replaced with 1 to get longest
// continuous sequence of 1s. If there is no 0 in array, then
// it returns -1.
static int maxOnesIndex(int arr[], int n)
{
int max_count = 0; // for maximum number of 1 around a zero
int max_index=0; // for storing result
int prev_zero = -1; // index of previous zero
int prev_prev_zero = -1; // index of previous to previous zero
// Traverse the input array
for (int curr=0; curr
{
// If current element is 0, then calculate the difference
// between curr and prev_prev_zero
if (arr[curr] == 0)
{
// Update result if count of 1s around prev_zero is more
if (curr - prev_prev_zero > max_count)
{
max_count = curr - prev_prev_zero;
max_index = prev_zero;
}
// Update for next iteration
prev_prev_zero = prev_zero;
prev_zero = curr;
}
}
// Check for the last encountered zero
if (n-prev_prev_zero > max_count)
max_index = prev_zero;
return max_index;
}
// Driver program to test above function
public static void main(String[] args)
{
int arr[] = {1, 1, 0, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1};
int n = arr.length;
System.out.println("Index of 0 to be replaced is "+
maxOnesIndex(arr, n));
}
}
Output:
Index of 0 to be replaced is 9
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