C++ Program to Solve any Linear Equation in One Variable

Code:

#include    iostream

struct VAR{
float i;
};

struct LINE{//k*x+a
float a, k;
VAR* x;

LINE(){}
LINE(int a) : a(a), k(0), x(0) {}
LINE(VAR& v) : a(0), k(1), x(&v) {}
};

LINE operator + (LINE A, LINE B){//assumes that A.x == 0 or B.x == 0 or A.x == B.x
LINE R;
R.a = A.a + B.a;
R.k = A.k + B.k;
if(A.x) R.x = A.x;
else R.x = B.x;
return R;
}

LINE operator - (LINE A, LINE B){//same as +
LINE R;
R.a = A.a - B.a;
R.k = A.k - B.k;
if(A.x) R.x = A.x;
else R.x = B.x;
return R;
}

LINE operator * (LINE A, LINE B){//assumes that A.x == 0 or B.x == 0
LINE R;
R.a = A.a * B.a;
R.k = A.k * B.a + B.k * A.a;
if(A.x) R.x = A.x;
else R.x = B.x;
return R;
}

LINE operator / (LINE A, LINE B){//assumes that B.x == 0
LINE R;
R.a = A.a / B.a;
R.k = A.k / B.a;
R.x = A.x;
return R;
}

void operator == (LINE A, LINE B){
LINE C = A - B;
C.x->i = -C.a/C.k;
}

int main(){
VAR x;
5 == (2 + (x-7)*10)/2;

std::cout << "x = " << x.i;
std::cin.get();

return 0;
}



Output:

Execute and get the output.



More C++ Programs: