Code:
#include stdio.h
#include stdlib.h
struct node
{
int data;
struct node* left;
struct node* right;
};
void print_paths_recur(struct node* node, int path[], int path_len);
void print_array(int ints[], int len);
/*Function to store all the paths from the root node to all leaf nodes in a array*/
void print_paths(struct node* node)
{
int path[1000];
print_paths_recur(node, path, 0);
}
/*Function which helps the print_path to recursively print all the nodes*/
void print_paths_recur(struct node* node, int path[], int path_len)
{
if (node == NULL)
return;
path[path_len] = node->data;
path_len++;
if (node->left == NULL && node->right == NULL)
{
print_array(path, path_len);
}
else
{
print_paths_recur(node->left, path, path_len); //recursively calls the left node of the tree
print_paths_recur(node->right, path, path_len); //recursively calls the right node of the tree
}
}
/*Function to print all the paths */
void print_array(int ints[], int len)
{
int i;
for (i = 0; i < len; i++)
{
printf("%d -> ", ints[i]);
}
printf("\n");
}
struct node* newnode(int data)
{
struct node* node = (struct node*) malloc(sizeof(struct node));
node->data = data;
node->left = NULL;
node->right = NULL;
return(node);
}
int main()
{
/*
The input tree is as shown below
40
/ \
20 60
/ \ \
10 30 80
\
90
*/
struct node *root = newnode(40);
root->left = newnode(20);
root->right = newnode(60);
root->left->left = newnode(10);
root->left->right = newnode(30);
root->right->right = newnode(80);
root->right->right->right = newnode(90);
print_paths(root);
return 0;
}
Output:
40 -> 20 -> 10 ->
40 -> 20 -> 30 ->
40 -> 60 -> 80 -> 90 ->
More C Programs: