Thursday, 23 November 2017

C++ Program to Implement Network_Flow Problem


Code:

#include   iostream
#include   climits
#include   cstring
#include   queue
#define V 6
using namespace std;

/*
 *  Returns true if there is a path from source 's' to sink 't' in
 * residual graph. Also fills parent[] to store the path *
 */
bool bfs(int rGraph[V][V], int s, int t, int parent[])
{
    bool visited[V];
    memset(visited, 0, sizeof(visited));
    queue q;
    q.push(s);
    visited[s] = true;
    parent[s] = -1;
    while (!q.empty())
    {
        int u = q.front();
        q.pop();

        for (int v=0; v
        {
            if (visited[v]==false && rGraph[u][v] > 0)
            {
                q.push(v);
                parent[v] = u;
                visited[v] = true;
            }
        }
    }
    return (visited[t] == true);
}

/*
 *  Returns tne maximum flow from s to t in the given graph
 */
int fordFulkerson(int graph[V][V], int s, int t)
{
    int u, v;
    int rGraph[V][V];
    for (u = 0; u < V; u++)
    {
        for (v = 0; v < V; v++)
             rGraph[u][v] = graph[u][v];
    }
    int parent[V];
    int max_flow = 0;

    while (bfs(rGraph, s, t, parent))
    {
        int path_flow = INT_MAX;
        for (v=t; v!=s; v=parent[v])
        {
            u = parent[v];
            path_flow = min(path_flow, rGraph[u][v]);
        }
        for (v = t; v != s; v = parent[v])
        {
            u = parent[v];
            rGraph[u][v] -= path_flow;
            rGraph[v][u] += path_flow;
        }
        max_flow += path_flow;
    }
    return max_flow;
}
/*
 * Main Contains Menu
 */ 
int main()
{
    int graph[V][V] = { {0, 16, 13, 0, 0, 0},
                        {0, 0, 10, 12, 0, 0},
                        {0, 4, 0, 0, 14, 0},
                        {0, 0, 9, 0, 0, 20},
                        {0, 0, 0, 7, 0, 4},
                        {0, 0, 0, 0, 0, 0}
                      };

    cout << "The maximum possible flow is " << fordFulkerson(graph, 0, 5);

    return 0;
}


Output:

The maximum possible flow is 23

------------------
(program exited with code: 0)
Press return to continue


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