Code:
#include stdio.h
void main()
{
int array[10];
int i, num, keynum, found = 0;
printf("Enter the value of num \n");
scanf("%d", &num);
printf("Enter the elements one by one \n");
for (i = 0; i < num; i++)
{
scanf("%d", &array[i]);
}
printf("Input array is \n");
for (i = 0; i < num; i++)
{
printf("%dn", array[i]);
}
printf("Enter the element to be searched \n");
scanf("%d", &keynum);
/* Linear search begins */
for (i = 0; i < num ; i++)
{
if (keynum == array[i] )
{
found = 1;
break;
}
}
if (found == 1)
printf("Element is present in the array\n");
else
printf("Element is not present in the array\n");
}
Output:
Enter the value of num
5
Enter the elements one by one
456
78
90
40
100
Input array is
456
78
90
40
100
Enter the element to be searched
70
Element is not present in the array
$ a.out
Enter the value of num
7
Enter the elements one by one
45
56
89
56
90
23
10
Input array is
45
56
89
56
90
23
10
Enter the element to be searched
45
Element is present in the array
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