Saturday 18 November 2017

C++ Program to Implement Booth’s Multiplication Algorithm for Multiplication of 2 signed Numbers


Code:

#include  iostream
#include  conio.h

using namespace std;

void add(int a[], int x[], int qrn);
void complement(int a[], int n)
{
    int i;

    int x[8] = { NULL };
    x[0] = 1;
    for (i = 0; i < n; i++)
    {
        a[i] = (a[i] + 1) % 2;
    }
    add(a, x, n);
}

void add(int ac[], int x[], int qrn)
{
    int i, c = 0;
    for (i = 0; i < qrn; i++)
    {
        ac[i] = ac[i] + x[i] + c;
        if (ac[i] > 1)
        {
            ac[i] = ac[i] % 2;
            c = 1;
        }
        else
            c = 0;
    }

}

void ashr(int ac[], int qr[], int &qn, int qrn)
{
    int temp, i;

    temp = ac[0];
    qn = qr[0];
    cout << "\t\tashr\t\t";
    for (i = 0; i < qrn - 1; i++)
    {
        ac[i] = ac[i + 1];
        qr[i] = qr[i + 1];
    }
    qr[qrn - 1] = temp;
}

void display(int ac[], int qr[], int qrn)
{
    int i;

    for (i = qrn - 1; i >= 0; i--)
        cout << ac[i];
    cout << " ";
    for (i = qrn - 1; i >= 0; i--)
        cout << qr[i];

}

int main(int argc, char **argv)
{
    int mt[10], br[10], qr[10], sc, ac[10] = { 0 };
    int brn, qrn, i, qn, temp;
    cout
            << "\n--Enter the multiplicand and multipier in signed 2's complement form if negative--";

    cout << "\n Number of multiplicand bit=";
    cin >> brn;
    cout << "\nmultiplicand=";

    for (i = brn - 1; i >= 0; i--)
        cin >> br[i]; //multiplicand

    for (i = brn - 1; i >= 0; i--)
        mt[i] = br[i]; // copy multipier to temp array mt[]

    complement(mt, brn);

    cout << "\nNo. of multiplier bit=";
    cin >> qrn;

    sc = qrn; //sequence counter

    cout << "Multiplier=";
    for (i = qrn - 1; i >= 0; i--)
        cin >> qr[i]; //multiplier


    qn = 0;
    temp = 0;

    cout << "qn\tq[n+1]\t\tBR\t\tAC\tQR\t\tsc\n";
    cout << "\t\t\tinitial\t\t";
    display(ac, qr, qrn);
    cout << "\t\t" << sc << "\n";

    while (sc != 0)
    {
        cout << qr[0] << "\t" << qn;
        if ((qn + qr[0]) == 1)
        {
            if (temp == 0)
            {
                add(ac, mt, qrn);
                cout << "\t\tsubtracting BR\t";
                for (i = qrn - 1; i >= 0; i--)
                    cout << ac[i];
                temp = 1;
            }
            else if (temp == 1)
            {
                add(ac, br, qrn);
                cout << "\t\tadding BR\t";
                for (i = qrn - 1; i >= 0; i--)
                    cout << ac[i];
                temp = 0;
            }
            cout << "\n\t";
            ashr(ac, qr, qn, qrn);
        }
        else if (qn - qr[0] == 0)
            ashr(ac, qr, qn, qrn);

        display(ac, qr, qrn);
        cout << "\t";

        sc--;
        cout << "\t" << sc << "\n";
    }
    cout << "Result=";
    display(ac, qr, qrn);
}



Output:

--Enter the multiplicand and multipier in signed 2's complement form if negative--
Number of multiplicand bit=5
Multiplicand=1 0 1 1 1

Number of multiplier bit=5
Multiplier=1 0 0 1 1

qn q[n+1] BR AC QR sc
initial 00000 10011 5
1 0 subtracting BR 01001
ashr 00100 11001 4
1 1 ashr 00010 01100 3
0 1 adding BR 11001
ashr 11100 10110 2
0 0 ashr 11110 01011 1
1 0 subtracting BR 00111
ashr 00011 10101 0

Result=00011 10101



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