C Program to do the Sum of the Main & Opposite Diagonal Elements of a MxN Matrix

Code:

#include

void main ()
{
    static int array[10][10];
    int i, j, m, n, a = 0, sum = 0;

    printf("Enter the order of the matix \n");
    scanf("%d %d", &m, &n);
    if (m == n )
    {
        printf("Enter the co-efficients of the matrix\n");
        for (i = 0; i < m; ++i)
        {
            for (j = 0; j < n; ++j)
            {
                scanf("%d", &array[i][j]);
            }
        }
        printf("The given matrix is \n");
        for (i = 0; i < m; ++i)
        {
            for (j = 0; j < n; ++j)
            {
                printf(" %d", array[i][j]);
            }
            printf("\n");
        }
        for (i = 0; i < m; ++i)
        {
            sum = sum + array[i][i];
            a = a + array[i][m - i - 1];
        }
        printf("\nThe sum of the main diagonal elements is = %d\n", sum);
        printf("The sum of the off diagonal elemets is   = %d\n", a);
    }
    else
        printf("The given order is not square matrix\n");
}

Output:

Enter the order of the matix
2 2
Enter the co-efficients of the matrix
40 30
38 90
The given matrix is
 40 30
 38 90

The sum of the main diagonal elements is = 130
The sum of the off diagonal elemets is   = 68

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