Thursday 23 November 2017

C++ Program to Check if a Binary Tree is a BST


Code:

#include    iostream
#include    cstdlib
#include    climits
using namespace std;

/* 
 * Node Declaration 
 */
struct node
{
    int data;
    node* left;
    node* right;
};

int isBSTUtil(node* node, int min, int max);

/* 
 * Returns true if the given tree is a binary search tree 
 */
int isBST(node* node)
{
    return(isBSTUtil(node, INT_MIN, INT_MAX));
}

/* 
 * Returns true if the given tree is a BST and its
 * values are >= min and <= max. 
 */
int isBSTUtil(struct node* node, int min, int max)
{
    if (node==NULL)
        return 1;
    if (node->data < min || node->data > max)
        return 0;
    return isBSTUtil(node->left, min, node->data - 1) &&  
            isBSTUtil(node->right, node->data + 1, max);
}

/* 
 * allocates a new node with the data and NULL left and right pointers. 
 */
node* newNode(int data)
{
    node* nod = new node;
    nod->data = data;
    nod->left = NULL;
    nod->right = NULL;
    return nod;
}

/* 
 * Main
 */
int main()
{
    node *root = newNode(4);
    root->left = newNode(2);
    root->right = newNode(5);
    root->left->left = newNode(1);
    root->left->right = newNode(3);
    if (isBST(root))
        cout<<"The Given Binary Tree is a BST"<
    else
        cout<<"The Given Binary Tree is not a BST"<
    return 0;
}


Output:

The Given Binary Tree is a BST

------------------
(program exited with code: 1)
Press return to continue



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